转自 http://blog.csdn.net/wusuopubupt/article/details/17284423
#include#include #include char *join1(char *, char*);void join2(char *, char *);char *join3(char *, char*);int main(void) { char a[4] = "abc"; // char *a = "abc" char b[4] = "def"; // char *b = "def" char *c = join3(a, b); printf("Concatenated String is %s\n", c); free(c); c = NULL; return 0;}/*方法一，不改变字符串a,b, 通过malloc，生成第三个字符串c, 返回局部指针变量*/char *join1(char *a, char *b) { char *c = (char *) malloc(strlen(a) + strlen(b) + 1); //局部变量，用malloc申请内存 if (c == NULL) exit (1); char *tempc = c; //把首地址存下来 while (*a != '\0') { *c++ = *a++; } while ((*c++ = *b++) != '\0') { ; } //注意，此时指针c已经指向拼接之后的字符串的结尾'\0' ! return tempc;//返回值是局部malloc申请的指针变量，需在函数调用结束后free之}/*方法二，直接改掉字符串a,*/void join2(char *a, char *b) { //注意，如果在main函数里a,b定义的是字符串常量（如下）： //char *a = "abc"; //char *b = "def"; //那么join2是行不通的。 //必须这样定义： //char a[4] = "abc"; //char b[4] = "def"; while (*a != '\0') { a++; } while ((*a++ = *b++) != '\0') { ; }}/*方法三，调用C库函数,*/char* join3(char *s1, char *s2){ char *result = malloc(strlen(s1)+strlen(s2)+1);//+1 for the zero-terminator //in real code you would check for errors in malloc here if (result == NULL) exit (1); strcpy(result, s1); strcat(result, s2); return result;}